Correlations
Nuclear / correlations.yaml 10 records
1 section
correlations 10
correlations
B1
- name
- B1
- description
- H3BO3 + OH- <-> H4BO4-
- equation
- 10^(28.6059 + 0.012078*T + 1573.21/T - 13.2258*log10(T))
coefficients
- a
- 28.6059
- b
- 0.012078
- c
- 1,573.21
- d
- -13.2258
B2
- name
- B2
- description
- 2H3BO3 + OH- <-> H5B2O6- + H2O
- equation
- 10^(-18.7322 - 0.00033*T + 2756.1/T + 5.835*log10(T))
coefficients
- a
- -18.7322
- b
- -3.3000e-4
- c
- 2,756.1
- d
- 5.835
B3
- name
- B3
- description
- 3H3BO3 + OH- <-> H4B3O7- + 3H2O
- equation
- 10^(-7.85 - 0.00033*T + 3339.5/T + 1.497*log10(T))
coefficients
- a
- -7.85
- b
- -3.3000e-4
- c
- 3,339.5
- d
- 1.497
B4
- name
- B4
- description
- 3H3BO3 <-> H3B3O6 + 3H2O
- equation
- 10^(0.54558 - 2248.91/T)
coefficients
- a
- 0.54558
- b
- -2,248.91
W1
- name
- W1
- description
- Water auto-ionization: H2O <-> H+ + OH-
- equation
- 10^(-4.098 - 3245.2/T + 2.2362e5/T^2 - 3.9984e7/T^3 + log10(rho)*(13.957 - 1262.3/T + 8.5641e5/T^2))
coefficients
- a0
- -4.098
- a1
- -3,245.2
- a2
- 223,620
- a3
- -3.9984e+7
- b0
- 13.957
- b1
- -1,262.3
- b2
- 856,410
input variables (2)
T [K], rho [kg/m^3]
L1
- name
- L1
- description
- LiOH dissociation: LiOH <-> Li+ + OH-
- equation
- 6120.376 - 169084.6/T + 1.784478*T - 1067.556*log10(T)
- note
- Returns Ke directly, not log10(Ke)
coefficients
- a
- 6,120.376
- b
- -169,084.6
- c
- 1.784478
- d
- -1,067.556
L2
- name
- L2
- description
- LiOH dissociation (density-dependent form)
- equation
- 0.856 + 135.60/T - (11.998 - 4226.4/T)*log10(rho)
coefficients
- a
- 0.856
- b
- 135.6
- c
- -11.998
- d
- 4,226.4
input variables (2)
T [K], rho
P1
- name
- P1
- description
- LiBO2 hydrolysis: LiBO2 + H2O + H+ <-> Li+ + H3BO3
- equation
- 10^(5.249217 + 1185.683/T)
coefficients
- a
- 5.249217
- b
- 1,185.683
P2
- name
- P2
- description
- LiBO2 precipitation equilibrium (variant 2)
- equation
- 10^(20.84423 - 86.74395/T - 4.85*log10(T))
coefficients
- a
- 20.84423
- b
- -86.74395
- c
- -4.85
P3
- name
- P3
- description
- LiBO2 precipitation equilibrium (variant 3)
- equation
- 10^(-11.19885 + 2531.538/T + 5.1128*log10(T))
coefficients
- a
- -11.19885
- b
- 2,531.538
- c
- 5.1128